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255C · Almost Arithmetical Progression

1500 · brute force, dp

Problem: Gena loves sequences of numbers. Recently, he has discovered a new type of sequences which he called an almost arithmetical progression. A sequence is an almost arithmetical progression, if its elements can be represented as:

  • a1 = p, where p is some integer;
  • ai = ai - 1 + ( - 1)i + 1·q (i > 1), where q is some integer.

Right now Gena has a piece of paper with sequence b, consisting of n integers. Help Gena, find there the longest subsequence of integers that is an almost arithmetical progression.

Sequence s1, s2, ..., sk is a subsequence of sequence b1, b2, ..., bn, if there is such increasing sequence of indexes i1, i2, ..., ik (1 ≤ i1 < i2 < ... < ik ≤ n), that bij = sj. In other words, sequence s can be obtained from b by crossing out some elements.

Input Format: The first line contains integer n (1 ≤ n ≤ 4000). The next line contains n integers b1, b2, ..., bn (1 ≤ bi ≤ 106).

Output Format: Print a single integer — the length of the required longest subsequence.

Note: In the first test the sequence actually is the suitable subsequence.

In the second test the following subsequence fits: 10, 20, 10.

Sample Cases

Case 1

Input

2
3 5

Output

2

Case 2

Input

4
10 20 10 30

Output

3

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