1805E · There Should Be a Lot of Maximums

Problem: You are given a tree (a connected graph without cycles). Each vertex of the tree contains an integer. Let's define the $\mathrm{MAD}$ (maximum double) parameter of the tree as the maximum integer that occurs in the vertices of the tree at least $2$ times. If no number occurs in the tree more than once, then we assume $\mathrm{MAD}=0$.

Note that if you remove an edge from the tree, it splits into two trees. Let's compute the $\mathrm{MAD}$ parameters of the two trees and take the maximum of the two values. Let the result be the value of the deleted edge.

For each edge, find its value. Note that we don't actually delete any edges from the tree, the values are to be found independently.

Input Format: The first line contains one integer $n$ ($2 \le n \le 10^5$) — the number of vertices in the tree.

Each of the next $n - 1$ lines contains two integers $u$ and $v$ ($1 \le u, v \le n$) — the ends of an edge of the tree. It's guaranteed that the given edges form a valid tree.

The last line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the numbers in the vertices.

Output Format: For each edge in the input order, print one number — the maximum of the $\mathrm{MAD}$ parameters of the two trees obtained after removing the given edge from the initial tree.

Note: In the first example, after removing edge $(1, 2)$ no number repeats $2$ times in any of the resulting subtrees, so the answer is $\max(0, 0)=0$.

After removing edge $(2, 3)$, in the bigger subtree, $1$ is repeated twice, and $2$ is repeated twice, so the $\mathrm{MAD}$ of this tree is $2$.

After removing edge $(2, 4)$, in the bigger subtree, only the number $1$ is repeated, and in the second subtree, only one number appears, so the answer is $1$.

In the second example, if edge $1 \leftrightarrow 4$ is not removed, then one of the subtrees will have two $1$, so the answer — $1$. And if edge $1 \leftrightarrow 4$ is deleted, both subtrees have no repeating values, so the answer is $0$.